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Ap® physics 2 2015 scoring guidelines ( ) - college ...

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Would be zero, which is less than the current through bulb 1. note: no points will be awarded for indicating that bulb1 is brighter than bulb 2. 9 pages
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AP® PHYSICS 22015 SCORING GUIDELINESQuestion 212 points total Distributionof points© 2015 The College Board.Visit the College Board on the Web: www.collegeboard.org.(a)i) 3 pointsFor indicating that eqR of the entire circuit or the combination of bulbs 2 and 3decreases1 pointFor indicating a change in totI or the potential difference across bulb 1 consistentwith Ohm’s law and the change in eqR stated in the response1 pointFor indicating a change in brightness consistent with the current or potentialdifference change stated in the response1 pointii) 3 pointsFor indicating that ( )2114P Re= 1 pointFor indicating that the new equivalent resistance of the circuit is ( )eq,new 3 2R R= 1 pointNote: Credit is earned if calculation is done in part (i) and used here.For manipulating equations to show that the power expended by bulb 1 isnew 1169P P=1 pointiii) 1 pointFor using or referring to the expression from part (a)(ii) to support the claim madein (a)(i) regarding the brightness of bulb 1: ...